[Author Prev][Author Next][Thread Prev][Thread Next][Author Index][Thread Index]

*To*: Alexei M Voloshin <Alexei.M.Voloshin-1@tc.umn.edu>*Subject*: Re: some calculations*From*: Withu Ruksvanichpongs <withu@lox2.loxinfo.co.th>*Date*: Wed, 14 Aug 1996 11:53:54 +0700 (GMT+0700)*Cc*: quattro@coimbra.ans.net*In-Reply-To*: <Pine.SOL.3.91.960813143142.23783A-100000@maroon.tc.umn.edu>*Reply-To*: Withu Ruksvanichpongs <withu@lox2.loxinfo.co.th>*Sender*: owner-quattro@coimbra.ans.net

I haven't try it yet ,because I don't know the frontal area of my car. In the article ,they try to tell us how much more power we need just to increase top speed a few mph. their example is Porsche 944 Cd 0.33 frontal area of 20.45 sq ft. assume the target speed is 200 mph Power needed is 8.7E-06*0.33*20.45*200^ = 469.8 HP. Oh,I just see the other one. new power/old power = (new speed/old speed)^3 Their Porsche now has 331 rear wheel h.p. and does 175 mph . they input these info. in the second formular and use 200 mph as new speed ,the new power is 493 which is very similar to 469.8 from the first formular. I don't think it is very accurate ,because many tuned German sedan also does 175 mph with about 300 *flywheel h.p.* (all of their h.p. means rear wheel h.p.,which is much lower than flywheel h.p.) Now I'll try the second formular for my car,but I'll use flywheel h.p. anyway. old speed=150 old power =230 new speed=? new power = 280 the answer is 160 mph.. they convert Porsche's331 pony in to flywheel h.p. of 400.!) 469.8 h.p. they need is still a rear wheel h.p. figure..!! I hope this is detailed enough Ben

**Follow-Ups**:**Re: some calculations***From:*Alexei M Voloshin <Alexei.M.Voloshin-1@tc.umn.edu>

**References**:**Re: some calculations***From:*Alexei M Voloshin <Alexei.M.Voloshin-1@tc.umn.edu>

- Prev by Author:
**Re: some calculations** - Next by Author:
**Schaumburg throttle body** - Prev by thread:
**Re: some calculations** - Next by thread:
**Re: some calculations** - Index(es):