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Re: Piston acceleration (was interferance etc)
glen powell wrote:
> Conceptually, I find it difficult to understand how acceleration is greatest
> at TDC, as the piston stops moving up, is momentarily motionless, and
> the starts to accelerate downward. How can acceleration be greatest at the
> instant in time that upward motion has ceased, the piston is motionless
> and then downward acceleration commences?
OK, let me give it a shot:
1. Piston has zero velocity both at the top and bottom of
2. It follows, therefore, that it has *maximum* velocity somewhere in
3. It has maximum positive velocity on the way up, and
maximum negative velocity on the way down.
4. To go from maximum positive velocity to maximum
negative velocity, it has to decelerate (or
negatively accelerate) continuously*.
5. Acceleration is defined as the instantaneous
(i.e. at any given point in time) rate of change of velocity.
6. It doesn't follow from the above, but because of the
nature of the piston/crankshaft mechanism, the velocity doesn't
have a constant rate of change between maximum positive and
maximum negative values.
7. It so happens that the maximum rate of change occurs at the
point at which velocity changes direction (i.e. when it is
It's fairly simple math, but either requires basic calculus,
or better ASCII art than I'm capable of!
Hope that helps!
*Continuous acceleration doesn't follow from statements
1-3: it's a consequence of the mechanical arrangement.